0=-16t^2+80t-100

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Solution for 0=-16t^2+80t-100 equation: 



0=-16t^2+80t-100

We move all terms to the left:

0-(-16t^2+80t-100)=0

We add all the numbers together, and all the variables

-(-16t^2+80t-100)=0

We get rid of parentheses

16t^2-80t+100=0

a = 16; b = -80; c = +100;
Δ = b2-4ac
Δ = -802-4·16·100
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{80}{32}=2+1/2$

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